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Revert "use sizeof(expr) for unevaluated syntax check"
Using sizeof(expr) can trigger a compile-time error,
"lambda expressions are not allowed in an unevaluated context", when passing
expression containing lambda, like a std algorithm. This error is considered
a standard defect, as it is meant to prevent lambdas in decltype
or templates, but not in sizeof.
This reverts commit 227598af47
.
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@ -40,7 +40,8 @@
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__catchResult.useActiveException( resultDisposition ); \
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} \
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INTERNAL_CATCH_REACT( __catchResult ) \
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} while( Catch::alwaysFalse( sizeof(expr) ) ) // expr here is never evaluated at runtime but it forces the compiler to give it a look
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} while( Catch::isTrue( false && static_cast<bool>( !!(expr) ) ) ) // expr here is never evaluated at runtime but it forces the compiler to give it a look
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// The double negation silences MSVC's C4800 warning, the static_cast forces short-circuit evaluation if the type has overloaded &&.
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///////////////////////////////////////////////////////////////////////////////
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#define INTERNAL_CATCH_IF( expr, resultDisposition, macroName ) \
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@ -119,8 +119,9 @@ namespace Catch {
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std::ostream& operator << ( std::ostream& os, SourceLineInfo const& info );
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// This is just here to avoid compiler warnings with macro constants and boolean literals
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inline bool alwaysTrue( std::size_t = 0 ) { return true; }
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inline bool alwaysFalse( std::size_t = 0 ) { return false; }
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inline bool isTrue( bool value ){ return value; }
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inline bool alwaysTrue() { return true; }
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inline bool alwaysFalse() { return false; }
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void throwLogicError( std::string const& message, SourceLineInfo const& locationInfo );
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